(int )_(-3)^3sqrt (9-{x)^2}dx= ． ．
[题目]利用定积分的几何意义,求 (int )_(-3)^3sqrt (9-{x)^2}dx.
定积分int_0^3(sqrt(9-{x^2))}dx的值为 ____ ．定积分$\int_0^3$${\sqrt{9-{x^2}}}$dx的值为 ____ ．
求定积分 (int )_(0)^3dfrac (dx)(x+sqrt {9-{x)^2}} 的值.
(1) int dfrac (3sqrt {x)}(x(sqrt {x)+sqrt [3](x))}dx
sqrt (9-{x)^2}+C
2、已知 (x)=sqrt (9-{x)^2}, 则f[f(t)]为 ()-|||-(A) sqrt (9-sqrt {9-{t)^2}}; (B)t; (C)
(3)(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);
定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0
(9) int (e)^sqrt [3](x)dx;