.已知 (dfrac (1)(x))=dfrac (4)(x)+2(x)^2+1, 求f(x), ((x)^2+1)
[题目]设 (dfrac (1)(x))=dfrac (x)({x)^2+1} 则 f(x)=
10.求下列函数的极值:-|||-(1) (x)=|x((x)^2-1)|;-|||-(2) (x)=dfrac (x({x)^2+1)}({x)^4-(x)^
7.已知函数 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2} ,则 f(x)=-|||-__
设函数=dfrac ({x)^2}(x-1),则=dfrac ({x)^2}(x-1)=________.设函数,则=________.
函数(x)=dfrac (1)(x-2)的间断点是(x)=dfrac (1)(x-2)(x)=dfrac (1)(x-2)、(x)=dfrac (1)(x-2)
已知 (x)=dfrac (x)(1+2x) 则 ^-1(1)=已知 (x)=dfrac (x)(1+2x) 则 ^-1(1)=
求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^d
(1)已知 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)= __ ;
【题文】已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2},求(x+dfrac (1)(x))=(x)^2+dfrac (1)(