设函数 f(x) 在 x=0 处可导，则 lim_(h arrow 0) (f(2h)-f(-3h))/(h) = （ ）A. $ -f'(0) $B. $ f
(f(x)在 _{0)=(x)_(0) 处可导,且 lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0)-h)}(2h)=
13、单选 lim_(x to x_{0)}f(x)=f(x_(0))是函数y=f(x)在x_(0)处连续的（）条件.A. 充分B. 必要C. 充要D. 无关
（函数极限058）设lim_(xto x_{0)}f(x)=a，则lim_(xto x_{0)}[f(x)]^n=（）A. 2aB. a^nC. caD. a^
若函数f（x）在点x0处可导，则极限underset(lim)(h→0)(f（(x)_(0)+3h）-f（(x)_(0)-h）)/(2h)=（ ）A. 4f′（
(1)若f(x)在 =(x)_(0) 处可导,则 () .-|||-(A) lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_
46、若y=f(x)在x_(0)处不可导，则曲线y=f(x)在点(x_(0),f(x_(0)))处没有切线.A. 正确B. 错误
(2)已知f(x)在 =(x)_(0) 处可导,且有 lim _(harrow 0)dfrac (2h)(f({x)_(0))-f((x)_(0)-4h)}=-
已知函数f(x)在点x0处可导,则下列极 限 中 () 等于导数值f`(x0).-|||-(A) lim _(harrow 0)dfrac (f({x)_(0)
(6)设f(x)在x0处可导,则 lim _(harrow 0)dfrac (f({x)_(0)+h)-f((x)_(0)-h)}(h)= () ;-|||-(