定积分 ^2-dfrac (1)(x)+C ()()-|||-A dfrac (1)(2)(x)^2+dfrac (1)(x)+C-|||-B dfrac (1
dfrac (1)(5)(X)_(1)+dfrac (2)(5)(X)_(2)+dfrac (2)(5)(X)_(3)-|||-D .dfrac (1)(7)(
dfrac (1)(x) C. -dfrac (1)({x)^2} D. dfrac (2)({x)^3}
[题目]若 (dfrac (1)(x))=x, 则 (x)= ()-|||-A、 dfrac (1)(x)-|||-B、 dfrac (1)({x)^2}-||
1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac
lim _(xarrow 1)(dfrac (a)(1-{x)^2}+dfrac (x)(x-1))=dfrac (3)(2) = __
函数(x)=dfrac (1)(x-2)的间断点是(x)=dfrac (1)(x-2)(x)=dfrac (1)(x-2)、(x)=dfrac (1)(x-2)
(2) lim _(xarrow infty )((dfrac {x+1)(x-1))}^-dfrac (x{2)}= () ;-|||-(A)1 (B) ^d
【题文】已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2},求(x+dfrac (1)(x))=(x)^2+dfrac (1)(
函数(x)=dfrac (1)(3)(x)^3+dfrac (1)(2)(x)^2的单调递增区间是( )A.(x)=dfrac (1)(3)(x)^