[题目]-|||-计算 https:/img.zuoyebang.cc/zyb_52d4b2f30ca827810621e201c6d77cd7.jpg=iint sqrt ({x)^2+(y)^2}dxdy, 其中-|||-D: leqslant yleqslant x, ^2+(y)^2leqslant 2x.

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https:/img.zuoyebang.cc/zyb_7951f03ce916a2297d2b38782b6a2474.jpg+(a)^2-|||-https:/img.zuoyebang.cc/z

https:/img.zuoyebang.cc/zyb_7951f03ce916a2297d2b38782b6a2474.jpg+(a)^2-|||-https

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    • 1/2 倍;-|||-C. https:/img.zuoyebang.cc/zyb_61825a25acb164a4803426e2b1e1d552.jpg/sqrt (2) 倍; D. sqrt (

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    https:/img.zuoyebang.cc/zyb_c0fbf0d3ab9a0b30a20e47b6f2b25ba5.jpg-a-|||-C.α^2 D.

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    • *(CO)=0.678 . https:/img.zuoyebang.cc/zyb_d7bd9e4c4e6bf8bf7c5501cba60ee7e8.jpg(x(y)_(2))=0.107,-|||-

    *(CO)=0.678 . https:/img.zuoyebang.cc/zyb_d7bd9e4c4e6bf8bf7c5501cba60ee7e8.jpg(x

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    • 1/a-|||-C. https:/img.zuoyebang.cc/zyb_72416c45e6138dc30242ff6f64fbfa9d.jpg/sqrt (2a) D. https:/img.

    1/a-|||-C. https:/img.zuoyebang.cc/zyb_72416c45e6138dc30242ff6f64fbfa9d.jpg/sqrt

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    • [题目]-|||-设 =x+-|||-A 1/2-|||-B 2-|||-C e-|||-D https:/img.zuoyebang.cc/zyb_e34c85f1ac31daff50515e6e3

    [题目]-|||-设 =x+-|||-A 1/2-|||-B 2-|||-C e-|||-D https:/img.zuoyebang.cc/zyb_e34c8

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    • -- ------- ---.-|||-https:/img.zuoyebang.cc/zyb_7e73d39b432994fc88687ca8629a236b.jpg-|||------|||---

    -- ------- ---.-|||-https:/img.zuoyebang.cc/zyb_7e73d39b432994fc88687ca8629a236b

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    • https:/img.zuoyebang.cc/zyb_80bfe4c6d6a401d7fdb38d9bb62346e3.jpg+sqrt (3)i . C. sqrt (3)-i . D. sqrt

    https:/img.zuoyebang.cc/zyb_80bfe4c6d6a401d7fdb38d9bb62346e3.jpg+sqrt (3)i . C.

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    • sqrt [4](2) C. dfrac (1)(2) D. https:/img.zuoyebang.cc/zyb_8aa7776a94adbf79d8d68f0ee8c17321.jpg-dfra

    sqrt [4](2) C. dfrac (1)(2) D. https:/img.zuoyebang.cc/zyb_8aa7776a94adbf79d8d68

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    • 直线https:/img.zuoyebang.cc/zyb_3b22ae73d69b101d1bae06f562ca4bd9.jpg:dfrac (x+2)(3)=dfrac (y-6)(1)=dfr

    直线https:/img.zuoyebang.cc/zyb_3b22ae73d69b101d1bae06f562ca4bd9.jpg:dfrac (x+2)(3

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