定积分(int )_(0)^dfrac (pi {2)}(e)^xsin xdx的值是(int )_(0)^dfrac (pi {2)}(e)^xsin xdx(int )_(0)^dfrac (pi {2)}(e)^xsin xdx(int )_(0)^dfrac (pi {2)}(e)^xsin xdx(int )_(0)^dfrac (pi {2)}(e)^xsin xdx(int )_(0)^dfrac (pi {2)}(e)^xsin xdx

(int )_(0)^dfrac (pi {2)}xsin xdx= ()-|||-

(int )_(0)^dfrac (pi {2)}(e)^2xcos xdx

(int )_(0)^dfrac (pi {2)}(e)^2xcos xdx; ;

求 (int )_(0)^dfrac (pi {2)}(e)^2xcos xdx求

(9) (int )_(-dfrac {pi )(2)}^dfrac (pi {2)}|sin x|arctan (e)^xdx

(int )_(0)^dfrac (pi {4)}(tan )^2xdx=1-dfrac (pi )(4) __-|||-__下列式子或叙述不正确的是A.B.设

7.计算下列定积分:-|||-(1) (int )_(0)^1x(e)^-xdx ;-|||-(2)(int )_(1)^xxln xdx;-|||-(3) (

[题目]计算定积分: (int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (1)(2)xcos xdx.

(6) (int )_(0)^dfrac (pi {2)}(sin )^2xcos xdx;

设=(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (sin x)(1+{x)^2}(cos )^4xdx, =(in