(int )_(0)^dfrac (pi {2)}xsin xdx= ()-|||-

定积分(int )_(0)^dfrac (pi {2)}(e)^xsin xdx的值是(int )_(0)^dfrac (pi {2)}(e)^xsin xdx

(int )_(0)^dfrac (pi {2)}(e)^2xcos xdx

(int )_(0)^dfrac (pi {2)}(e)^2xcos xdx; ;

(int )_(0)^dfrac (pi {4)}(tan )^2xdx=1-dfrac (pi )(4) __-|||-__下列式子或叙述不正确的是A.B.设

(6) (int )_(0)^dfrac (pi {2)}(sin )^2xcos xdx;

求 (int )_(0)^dfrac (pi {2)}(e)^2xcos xdx求

(9) (int )_(-dfrac {pi )(2)}^dfrac (pi {2)}|sin x|arctan (e)^xdx

设=(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (sin x)(1+{x)^2}(cos )^4xdx, =(in

设函数f(x)以2π为周期,它在 [ -pi ,pi ) 上的表达式为 f(x)= {int )_(0)^pi xsin 2xdx,g(0)+s(pi )=

[题目]计算定积分: (int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (1)(2)xcos xdx.