154 设 lim _(xarrow {x)_(0)^+}f(x)=lim _(xarrow {x)_(0)^-}(x)=a, 则-|||-(A)f(x)在 =
设 函数 f ( x ) 在 x = 0 处可导,且lim _(xarrow 0)dfrac (f(2x)-f(0))(ln (1+3x))=1,则f(0)=(
[题目]设f(x )具有二阶连续导数,且f(0)-|||-=0, lim _(xarrow 0)dfrac (f(x))(|x|)=1 则 ()-|||-A.f
设f(x)的导数在 x=a 处连续,又 lim _(xarrow a)dfrac (f(x))(x-a)=-1, 则 __ 。
C. lim _(xarrow 0)dfrac (f(x))(x) 不存在.-|||-f(0)=0 ^11(0)=2.-|||-D.f(0)是f(x)的极小值.
(10)设函数f(x)的导数在点 x=a 处连续,又 lim _(xarrow a)dfrac (f(x))(x-a)=-1, 则 () .(10)设函数f(x
f(x)_ x=a 某邻域内有三阶连续导数,且-|||-(a)=f(a)=0f(a)neq 0 则-|||-A x=a 是f(x)的极小值点-|||-B x=a
1.设f(x)在x=0处可导,且f(0)=0,则lim _(xarrow 0)dfrac (f(3x)-f(x))(x)-|||-__=______.1.设f(
设y=f(x) 在x0处可导,且 ((x)_(0))=2, 则lim _(xarrow 0)dfrac (f({x)_(0)+2)x-f((x)_(0)-f(x
[题目]-|||-设 ((x)_(0))=3 则 lim _(xarrow 0)dfrac (f({x)_(0)+x)-f((x)_(0)-3x)}(x)= _