方程^4-3(x)^3+6x-4=0-|||-__的整数解的个数是（ ）。A、0B、1C、2D、3

过点(1,1,1)、 (-2,-2,2) 和(1,-1,1) 的平面方程是 ()-|||-A x+4z+3=0-|||-B x+3z-4=0-|||-C x+4

函数(x)=(x)^3-3x在x=____处取得极大值A 0B -1C 2D -3函数在x=____处取得极大值A0B-1C2D-3

5、求解下列方程。-|||-(1) ^4-3(x)^2+2=0;-|||-(2) ^4-3(x)^2-4=0;-|||-(3) ^2x-(e+1)(e)^x+e

函数__-|||-(x)=dfrac ({x)^2-x}({x)^2-1} sqrt (1+dfrac {1)({x)^2}}-|||-__的无穷间断点的个数为

求线性方程组_(1)+(x)_(2)+(x)_(3)+(x)_(4)=0-|||-_(2)+2(x)_(3)+2(x)_(4)=1-|||-_(1)+2(x)_

若方程组 ) 7(x)_(1)+8(x)_(2)+9(x)_(3)=0 -(x)_(2)+2(x)_(3)=0 2(x)_(2)+t(x)_(3)=0 .=

已知 a 1 -2 x1-|||-1 0 3 x2 =0-|||--2 1 1 x3有非零解,则（）A a=-3B a=3C a≠3D a≠-3已知

曲线 =(x-1)((x-2))^2((x-3))^3((x-4))^4 的拐点是 () .-|||-(A)(1,0) (B)(2,0) (C)(3,0) (D

、单选 设曲线为 =((x-1))^2((x-3))^2,-|||-其极值点个数为 ()()-|||-(4分-|||-A 0-|||-B 3-|||-C 1-|

x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2