A. $\int_{0}^{1}dx\int_{x}^{\sqrt{x}}f(x,y)dy$;
B. $\int_{0}^{1}dy\int_{\sqrt{y}}^{y}f(x,y)dx$;
C. $\int_{0}^{1}dx\int_{\sqrt{x}}^{x}f(x,y)dy$;
D. $\int_{0}^{1}dy\int_{y}^{\sqrt{y}}f(x,y)dx$;
19、已知平面有界区域D=(x,y)mid y^2leq x,x^2leq y，计算二重积分iintlimits_(D)(x-y+1)^2dxdy.19、(本题
(6)[2025，三]已知平面有界区域D=(x,y)mid y^2leq x,x^2leq y，计算二重积分iintlimits_(D)(x-y+1)^2dxd
20.[已知平面有界区域D=(x,y)mid x^2+y^2leq 4x,x^2+y^2leq 4y计算iintlimits_(D)(x-y)^2dxdy.20
已知平面有界区域D=(x,y)mid x^2+y^2leq 4x,x^2+y^2leq 4y，计算二重积分iintlimits_(D)(x-y)^2dxdy.(
设z=f(x,y)满足f(-x,y)=-f(x,y),而其积分区域D关于y轴对称,则 iintlimits_(D)f(x,y)dxdy=0A. 对B. 错
10.设f(x,y)=}x-y+1,x+yleqslant1, (1)/(sqrt(x^2)+y^(2)),x+y>1,.计算I=iintlimits_(D)f
4.判断题iintlimits_(D)sqrt(1-x^2)-y^(2)dsigma=4iintlimits_(D_{1)}sqrt(1-x^2)-y^(2)d
如果iintlimits_(D)f(x,y)dsigmageiintlimits_(D)g(x,y)dsigma，则f(x,y)≥g(x,y).A. 对B. 错
设 D=(x,y)|(x^2)/(9)+(y^2)/(4)leq 1，f(x,y)=1，则二重积分 iint_(D) f(x,y), dsigma=（）A. $
例1 将 iintlimits_(D)f(x,y)dx dy 化为累次积分，其中D由直线 y=x, y=x-2, y=2, y=4 围成。例1 将 $\iint