[题目]-|||-设 =sqrt (1+{x)^2} ,则 dy= __ ; ^n= __

1、设 =ln (arctan sqrt (1+{x)^2}) 求dy;

[题目]设 (x)=sqrt (1+{ln )^2x} 则 (e)=()-|||-A、 dfrac (sqrt {2)}(4)-|||-B、 dfrac (sq

[题目] int dfrac (xarctan x)(sqrt {1+{x)^2}}dx

[题目]求导数: =ln (x+sqrt (1+{x)^2})

化简n sqrt ({(1+{x)^2)}^3}=。化简。

设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|

(6)设 _(n)=dfrac (3)(2)(int )_(0)^dfrac (n{n+1)}(x)^n-1sqrt (1+{x)^n}dx, 则极限limna

[题目]-|||-int (dfrac (3)(1+{x)^2}-dfrac (2)(sqrt {1-{x)^2}})dx

设X~N(μ，σ²)，则概率P(X≤1+μ)=（）A. 随μ的增大而增大B. P(A)-P(B)+P(AB)C. 随σ的增加而增加;D. 随σ的增加而减小.

(2)设函数 (x)=lim _(narrow infty )sqrt [n](1+{|x|)^3n}, 则 f(x)在 (-infty ,+infty ) 内