1、设 =ln (arctan sqrt (1+{x)^2}) 求dy;

设 =ln (1+(sin )^2x), 求dy.

1.设 sin y+(e)^x-x(y)^2=0, 求 dfrac (dy)(dx).-|||-2.设 ln sqrt ({x)^2+(y)^2}=arctan

[题目]-|||-设 =sqrt (1+{x)^2} ,则 dy= __ ; ^n= __

设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|

求ln sqrt ({x)^2+(y)^2}=arctan dfrac (y)(x)的导数(dy)/(dx).求的导数$\frac{dy}{dx}$.

设 gt 0, 求 (int )_(-a)^asqrt ({a)^2-(x)^2}ln dfrac (x+sqrt {1+{x)^2}}(3)dx,

求下列极限-|||-lim _(xarrow 0)[ dfrac (1)(ln (x+sqrt {1+{x)^2})}-dfrac (1)(ln (1+x))]

求下列不定积分：int ln (sqrt (1+{x)^2}-x)dx。求下列不定积分：。

(2) (x)=ln (x+sqrt (1+{x)^2});

(19) int tan sqrt (1+{x)^2}cdot dfrac (xdx)(sqrt {1+{x)^2}}-|||-(20) int dfrac (