2x(1+x)-(x)^2-|||-7.设函数f(x)可导且 '(x)=dfrac (2x)(sqrt {{a)^2-(x)^2}} 求 dfrac (d)(dx)(f(sqrt ({a)^2-(x)^2}))

已知f(x)=(2x)/(sqrt (1-{x)^2)}，则(df(sqrt (1-{x)^2)})/(dx)=(,,,,,)A、-2；B、-dfrac(2x)

设=dfrac (2x)({x)^2-(y)^2} ，则 =dfrac (2x)({x)^2-(y)^2}=dfrac (2x)({x)^2-(y)^2}___

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x);-|||-(2) =xsin 2x;-|||-(3) =dfrac (x)(

求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x);-|||-(2) =xsin 2x;-|||-(3) =dfrac (x)(

(14) int dfrac ({x)^2}(sqrt {{a)^2-(x)^2}}dx;

3.求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x);-|||-(2) =xsin 2x;-|||-(3) =dfrac (x

3.求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x) =-|||-(2) =xsin 2x ;-|||-(3) =dfrac

(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x

设=dfrac (y)(f({x)^2-(y)^2)},其中f为可导函数.验证=dfrac (y)(f({x)^2-(y)^2)}.设,其中f为可导函数.验证.