( A ) = (x,y,z)|{x)^2+(y)^2+(z)^2=(a)^2,zgeqslant 0} ( B ) = (x,y,z)|{x)^2+(y)^2+(z)^2=(a)^2,zgeqslant 0} ( C ) = (x,y,z)|{x)^2+(y)^2+(z)^2=(a)^2,zgeqslant 0} ( D ) = (x,y,z)|{x)^2+(y)^2+(z)^2=(a)^2,zgeqslant 0}

球面^2+(y)^2+(z)^2+4x+6y+2z+10=0的球心坐标为A.^2+(y)^2+(z)^2+4x+6y+2z+10=0B.^2+(y)^2+(z)

设(x,y,z)=(x)^2+(y)^3+z,求(x,y,z)=(x)^2+(y)^3+z,在点(x,y,z)=(x)^2+(y)^3+z,处沿方向(x,y,z

函数(z)=(x)^2+(y)^2i ( ).A.仅在(z)=(x)^2+(y)^2i上解析;B.在除(z)=(x)^2+(y)^2i之外的复平面上

曲线 ) (x)^2-(y)^2+(z)^2=0 z=1 .曲线在坐标面上的投影曲线方程为______A.B.C.D.

设r=√(x-x ) (}^2+{(y-y))^2+((z-z))^2为源点x到场点X的距离，r的方向规定为从源点指向场点。r=√(x-x ) (}^2+{(y

设 ^2+(y)^2+(z)^2-4z=0, 求 dfrac ({a)^2z}(q{x)^2}

16.设函数 z=z(x,y) 由方程 ^2+(y)^2+(z)^2-6z=0 确定,求 dfrac ({sigma )^2z}(sigma x{U)_(y)}

[题目]设L为球面 ^2+(y)^2+(z)^2=(a)^22 被平面 x+y+z=0 所-|||-截的圆周,则 (int )_(1)((x)^2+(y)^2)

[题目]求函数 =(x)^2+(y)^2+(z)^2 在约束条件 =(x)^2+(y)^2 和-|||-x+y+z=4 下的最大值与最小值.

求指导本题解题过程，谢谢您！5.设Ω由曲面 =sqrt ({x)^2+(y)^2}, ^2+(y)^2+(z)^2=2z 围成将,则Ω和三重积分-|||-JJ