A、 dfrac (pi )(6) B、 dfrac (2pi )(3) C、 dfrac (4pi )(3) D、 dfrac (pi )(3)-|||-2、一简谐振动曲线如图所示,则该振动的初相为 ()-|||-A、 dfrac (pi )(6) B、 dfrac (2pi )(3) C、 -dfrac (2pi )(3) D、 -dfrac (pi )(6)-|||-x-|||-4-|||-o-|||-2 is-|||--2

参考答案与解析:

相关试题

两简谐振动的振动方程分别为_(1)=3cos (2pi t-dfrac (pi )(3)), _(2)=4cos (2pi t+dfrac (pi )(6))单位均为厘米 ) 合振幅为( A ) 5

两简谐振动的振动方程分别为_(1)=3cos (2pi t-dfrac (pi )(3)), _(2)=4cos (2pi t+dfrac (pi )(6))单

  • 查看答案
  • 质点作简谐运动,振动曲线如图所示,其振动方程的初相位φ为( )A.dfrac (pi )(2)B.dfrac (pi )(2)C.0D.πdfrac (pi )(2)

    质点作简谐运动,振动曲线如图所示,其振动方程的初相位φ为( )A.dfrac (pi )(2)B.dfrac (pi )(2)C.0D.πdfrac

  • 查看答案
  • dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)

    dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)

  • 查看答案
  • dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)

    dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)

  • 查看答案
  • (B) pi +dfrac (4)(3) (C) pi +2 . (D) pi +dfrac (8)(3)

    (B) pi +dfrac (4)(3) (C) pi +2 . (D) pi +dfrac (8)(3)

  • 查看答案
  • dfrac (pi )(3)B . dfrac (pi )(3)C . dfrac (pi )(3)D . dfrac (pi )(3)

    dfrac (pi )(3)B . dfrac (pi )(3)C . dfrac (pi )(3)D . dfrac (pi )(3)[单选题]复数1+i对应

  • 查看答案
  • (B) dfrac (lambda )(2pi {varepsilon )_(0)a}. (C) dfrac (lambda )(4pi {varepsilon )_(0)a}. (D) dfrac

    (B) dfrac (lambda )(2pi {varepsilon )_(0)a}. (C) dfrac (lambda )(4pi {varepsilon

  • 查看答案
  • 3.要使函数φ(x )= ,dfrac {pi )(2)] (B)[π,2π] (C) [ 0,dfrac (pi )(2)] (D) [ dfrac (pi )(2),pi ]

    3.要使函数φ(x )= ,dfrac {pi )(2)] (B)[π,2π] (C) [ 0,dfrac (pi )(2)] (D) [ dfrac

  • 查看答案
  • dfrac (qQ)(4pi {varepsilon )_(0)l} C. dfrac (qQ)(2pi {varepsilon )_(0)l} D. -dfrac (qQ)(2pi {varepsi

    dfrac (qQ)(4pi {varepsilon )_(0)l} C. dfrac (qQ)(2pi {varepsilon )_(0)l} D. -dfr

  • 查看答案
  • 9-6 图(a)中所画的是两个简谐振动的曲线,若这两个简谐振动可叠加,-|||-则合成的余弦振动的初相位为 ()-|||-(A) dfrac (3)(2)pi (B) dfrac (1)(2)pi

    9-6 图(a)中所画的是两个简谐振动的曲线,若这两个简谐振动可叠加,-|||-则合成的余弦振动的初相位为 ()-|||-(A) dfrac (3)(2)pi

  • 查看答案