设函数f(x)=(1)/(x),g(x)=1-x,则f[g(x)]=A. 1-$\frac{1}{x}$B. 1+$\frac{1}{x}$C. $\frac{
设(x)=dfrac (1-x)(1+x), 则(x)=dfrac (1-x)(1+x)设,则
设(x)=dfrac (1)(1-x), 求(x)=dfrac (1)(1-x)和(x)=dfrac (1)(1-x)设, 求和
[题目]-|||-6.设函数 (dfrac (1-x)(1+x))=x 则 f(x)= __
设函数f(x)=(1-x)/(1+x),则f[f(x)]= ____ .设函数f(x)=$\frac{1-x}{1+x}$,则f[f(x)]= ____ .
设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|
设函数 (x)=dfrac (1)({e)^dfrac (x{x-1)}-1} 则-|||-
设f(x)=e^x,f[g(x)]=1-x^2则g(x)=设$$f(x)=e^{x},f[g(x)]=1-x^2$$则$$g(x)$$$$=$$
设f(x)=(x)/(1-x),g(x)=(x)/(1+x),求复合函数f[f(x)],f[g(x)],g[f(x)],g[g(x)].设$f(x)=\frac