当x→1时，无穷小1-x和(1) 1-x^3;(-|||-(2) dfrac (1)(2)(1-(x)^2)是否同阶？是否等价？

设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|

1.单选题(1)当x→0时，f(x)=sin ax^3与g(x)=x^2ln(1-x)是等价无穷小，则（）A. a=1B. a=2C. a=-1D. a=-2

(1)当x→0时，f(x)=sin(ax^3)与g(x)=x^2ln(1-x)是等价无穷小量，则( ).A. a=1B. a=2C. a=-1D. a=-2

设(x)=dfrac (1)(1-x), 求(x)=dfrac (1)(1-x)和(x)=dfrac (1)(1-x)设, 求和

(3)设当x→0时, ^x-(a(x)^2+bx+1) 是比 x^2 高阶的无穷小,则 ()-|||-(A) =dfrac (1)(2) ,b=1 (B) a=

lim _(xarrow 1)dfrac (1-{x)^3}(1-x)

lim _(xarrow 1)(dfrac (1)(1-x)-dfrac (3)(1-{x)^3})-|||-__ __;;

lim _(xarrow 1)(dfrac (1)(1-x)-dfrac (3)(1-{x)^3})=-|||-_______._____.

lim _(xarrow 1)(dfrac (3)(1-{x)^3}-dfrac (1)(1-x))-|||-__。。

int dfrac ({(1-x))^2}(x(1+{x)^2)}dx