[题目]如果 (cos x)=dfrac ({sin )^2x}(cos 2x), 则 f(x)= () )-|||-

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __

[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

已知 (cos x)=(sin )^2x, 则 f(x)= __

[题目] (sin )^2x+(cos )^2x= __

int dfrac (cos 2x)(cos x+sin x)dx

求下列不定积分:-|||-(22) int dfrac (cos 2x)({cos )^2x(sin )^2x}dx ;

求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()求极限

cos 2x(e)^-x+ sin 2x(e)^-xdx-|||-B.cos2xe^(-x)- sin 2x(e)^-xdx-|||-. cos 2x(e)^