已知 (cos x)=(sin )^2x, 则 f(x)= __

[针对练1] 已知 (cos x)=(sin )^2x, 则 f(x)=-|||-__

[题目]如果 (cos x)=dfrac ({sin )^2x}(cos 2x), 则 f(x)= () )-|||-

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

cos 2x(e)^-x+ sin 2x(e)^-xdx-|||-B.cos2xe^(-x)- sin 2x(e)^-xdx-|||-. cos 2x(e)^

sin^2x+cos^2x=_____$$sin^2x+cos^2x=$$_____

int dfrac (cos 2x)(cos x+sin x)dx

函数f（x）=x-2sin(x)/(2)cos(x)/(2)，则f′（(π)/(3)）=（ ）A. 0B. $\frac{1}{2}$C. $\frac{\sq

函数f（x）=x-2sin(x)/(2)cos(x)/(2)，则f′（(π)/(4)）=（　　）函数f（x）=x-2sin$\frac{x}{2}$cos$\f

[题目] (sin )^2x+(cos )^2x= __

已知f（2x）=x2-2x，则f（x）=（ ）A. $\frac{1}{4}x^{2}+1$B. $\frac{1}{4}x^{2}-1$C. $\frac{1