[针对练1] 已知 (cos x)=(sin )^2x, 则 f(x)=-|||-__

已知 (cos x)=(sin )^2x, 则 f(x)= __

[题目]如果 (cos x)=dfrac ({sin )^2x}(cos 2x), 则 f(x)= () )-|||-

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

cos 2x(e)^-x+ sin 2x(e)^-xdx-|||-B.cos2xe^(-x)- sin 2x(e)^-xdx-|||-. cos 2x(e)^

sin^2x+cos^2x=_____$$sin^2x+cos^2x=$$_____

设函数 f(x)= x(e^2x - 1)，g(x)= 1 - cos(2x)，则当 x to 0 时，f(x) 是 g(x) 的(）A. 等价无穷小B. 同阶

8.设lim_(x to 0) (sin 2x + xf(x))/(x^3) = 1,则lim_(x to 0) (2cos x + f(x))/(x^2) =

)int dfrac (1)({cos )^2x(sin )^2x}dx.

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __

int dfrac (cos 2x)(cos x+sin x)dx