[针对练1] 已知 (cos x)=(sin )^2x, 则 f(x)=-|||-__

已知 (cos x)=(sin )^2x, 则 f(x)= __

[题目]如果 (cos x)=dfrac ({sin )^2x}(cos 2x), 则 f(x)= () )-|||-

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

cos 2x(e)^-x+ sin 2x(e)^-xdx-|||-B.cos2xe^(-x)- sin 2x(e)^-xdx-|||-. cos 2x(e)^

设函数 f(x)= x(e^2x - 1)，g(x)= 1 - cos(2x)，则当 x to 0 时，f(x) 是 g(x) 的(）A. 等价无穷小B. 同阶

8.设lim_(x to 0) (sin 2x + xf(x))/(x^3) = 1,则lim_(x to 0) (2cos x + f(x))/(x^2) =

sin^2x+cos^2x=_____$$sin^2x+cos^2x=$$_____

1.[单选题]已知f(x)=2x^2-3x+sin(pi)/(7)+ln2，则f^prime(x)=（）A. x-3B. 4xC. 4x+3D. 4x-3

函数f（x）=x-2sin(x)/(2)cos(x)/(2)，则f′（(π)/(4)）=（　　）函数f（x）=x-2sin$\frac{x}{2}$cos$\f

函数f（x）=x-2sin(x)/(2)cos(x)/(2)，则f′（(π)/(3)）=（ ）A. 0B. $\frac{1}{2}$C. $\frac{\sq