A. 高阶无穷小
B. 低阶无穷小
C. 同阶但非等价无穷小
D. 等价无穷小
5.当x→0时，e-e^cos x是sqrt[3](1+x^2)-1的（）.A. 高阶无穷小B. 低阶无穷小C. 同阶但非等价无穷小D. 等价无穷小
5.当x→0时,无穷小量 bigcirc (1)(e)^-(x^2)-1 ;② sqrt (1+2x)-sqrt (1+x) ;bigcirc (3)(e)^x
(3) (2009-3) lim_(x arrow 0) (e-e^cos x)/(sqrt[3](1+x^2)-1)(3) (2009-3) $\lim_{x
【例22】(2009,数三) lim _(x arrow 0) (e-e^cos x)/(sqrt[3](1+x^2)-1)=_.【例22】(2009,数三)
=(e)^2x-|||-2. =(e)^-(x^2)-|||-3. =dfrac ({e)^x}(1+x)-|||-4. =dfrac (sqrt {(x+1)
(8) lim _(xarrow 0)dfrac ({e)^3x-(e)^2x-(e)^x+1}(sqrt [3]{(1-x)(1+x))-1} .
[题目]-|||-求下列极限:-|||-lim _(xarrow 0)dfrac ({e)^3x-(e)^2x-(e)^x+1}(sqrt [3]{(1-x)(
求下列极限:-|||-__-|||-(8) lim _(xarrow 0)dfrac ({e)^3x-(e)^2x-(e)^x+1}(sqrt [3]{(1-x
underset(lim)(x→0)dfrac(1-sqrt(1-{x)^2)}({e)^x-cosx}= _____．= _____．
求极限 lim _(xarrow 0)dfrac ({x)^2((e)^x-1)}(sqrt {1+tan x)-sqrt (1+x)}