下列求导结果正确的是A (x+dfrac (1)(x))'=1-dfrac (1)({x)^2}B (x+dfrac (1)(x))'=1-dfrac (1)({x)^2}C (x+dfrac (1)(x))'=1-dfrac (1)({x)^2}D (x+dfrac (1)(x))'=1-dfrac (1)({x)^2}

【题文】已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}，求(x+dfrac (1)(x))=(x)^2+dfrac (1)(

A X=0 =1-dfrac (theta )(100), X=1 =dfrac (theta )(100). B X=0 =1-dfrac (theta

dfrac (1)(2)x+dfrac (1)(3)=dfrac (1)(4)x-dfrac (1)(5)

(1)已知 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)= __ ;

[题目]若 (dfrac (1)(x))=x, 则 (x)= ()-|||-A、 dfrac (1)(x)-|||-B、 dfrac (1)({x)^2}-||

[题目]设 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则f(x)= __

已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}-3，求f(x)已知，求f(x)

(B) dfrac (x)(y)((y+1))^2-|||-(C) ^2((x+dfrac {1)(x))}^2. (D) dfrac (y)(x)((y+1)

(2) lim _(xarrow 0)dfrac ({(1-dfrac {1)(2)(x)^2)}^dfrac (2{3)}-1}(xln (1+x))

已 知 函数 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)=-|||-__