A X=0 =1-dfrac (theta )(100), X=1 =dfrac (theta )(100). B X=0 =1-dfrac (theta )(100), X=1 =dfrac (theta )(100);C X=0 =1-dfrac (theta )(100), X=1 =dfrac (theta )(100)D X=0 =1-dfrac (theta )(100), X=1 =dfrac (theta )(100)

设总体X的概率分布为利用来自总体的样本值1,1,0,1,1,可得的矩估计值为().

A .

B ;

C

D

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