当x→1时,函数
的极限( )
(A)等于2
(B)等于0
(C)为∞
(D)不存在但不为∞
当x→1时,函数dfrac ({x)^2-1}(x-1)(e)^dfrac (1{x-1)}的极限( ) (A)等于2 (B)等于0 (C)为∞ (D)不
lim _(xarrow 1)dfrac ({x)^2-1}(x-1)(e)^dfrac (1{x-1)}=
2 , 1 B . 1 , 2 C . (x)=dfrac ({e)^x-1}(x), 1D . (x)=dfrac ({e)^x-1}(x), 2设函数,若当
5.设(x)=dfrac (|x-1|)(x-1),则(x)=dfrac (|x-1|)(x-1)________.A.等于零 B.等于1 C.等于-
设函数=dfrac ({x)^2}(x-1),则=dfrac ({x)^2}(x-1)=________.设函数,则=________.
lim _(xarrow 1)(dfrac (2)({x)^2-1}-dfrac (1)(x-1)) ;
计算下列极限:-|||-lim _(xarrow 1)(dfrac (2)({x)^2-1}-dfrac (1)(x-1)).
lim _(xarrow 1)(dfrac (2)({x)^2-1}-dfrac (1)(x-1))= (-|||-A.1 B. -dfrac (1)(2) C
设函数 (x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6}求(x)=(e)^dfrac (1{x-1)}dfra
(2) lim _(xarrow infty )((dfrac {x+1)(x-1))}^-dfrac (x{2)}= () ;-|||-(A)1 (B) ^d