160 求极限lim _(xarrow infty )(x)^2[ ln ((x)^2+1)-2ln x] = x]=

[题目]求极限 lim _(xarrow infty )[ x-(x)^2ln (1+dfrac (1)(x))] .

lim _(xarrow +infty )times 2[ ln (x2+1)-2ln x] = () .

求极限 lim _(xarrow +infty )dfrac (ln (x+sqrt {{x)^2+1})-ln (x+sqrt ({x)^2-1})}( l

求lim _(xarrow infty )[ x-(x)^2ln (1+dfrac (1)(x))] -|||-__求

25.[2019]求极限 lim _(xarrow infty )[ x-(x)^2ln (1+dfrac (1)(x)] )

1、求极限 lim _(xarrow 0)dfrac (x-sin x)({x)^2ln (1+2x)}

求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^d

lim _(xarrow infty )3x-(x)^2ln (1+dfrac (3)(x))

2.求极限 lim _(xarrow +infty )arcsin dfrac (x)(sqrt {{x)^2+1}+x}

求lim _(xarrow +infty )x(sqrt ({x)^2+1}-x)求