

函数 y=ln (x+sqrt(x^2+1)) 是()。A. 奇函数B. 偶函数C. 非奇非偶函数D. 既是奇函数又是偶函数
证明函数(x)=ln (x+sqrt ({x)^2+1})为奇函数.证明函数为奇函数.
求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^d
求极限 lim _(xarrow +infty )dfrac (ln (x+sqrt {{x)^2+1})-ln (x+sqrt ({x)^2-1})}( l
[题目]已知函数 =ln (x+sqrt ({a)^2+(x)^2}) 求y`.
(1) =ln (x+sqrt ({x)^2+1})
函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B
求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x);-|||-(2) =xsin 2x;-|||-(3) =dfrac (x)(
求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x);-|||-(2) =xsin 2x;-|||-(3) =dfrac (x)(
=ln (x+sqrt ({a)^2+(x)^2});