求int dfrac (1)({x)^2-x-2}dx

int dfrac (5x-1)({x)^2-x-2}dx= (.A.int dfrac (5x-1)({x)^2-x-2}dx= (B.int dfrac (

(35) int dfrac (x)({x)^2-x-2}dx;

计算：int dfrac (x)({x)^2-x-2}dx计算：

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

2.求下列不定积分:-|||-(1) int dfrac (dx)({x)^2};-|||-(2) int xsqrt (x)dx; 2.求下列不定积

例2 求 int dfrac (dx)(1+{x)^2} =

1.求下列不定积分:-|||-(1) int dfrac ({x)^3}(x-1)dx;-|||-(2) int dfrac (x-2)({x)^2-7x+12

求(int )_(0)^2dfrac (dx)({(1-x))^2}求

int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df

函数(x)=dfrac (1)({x)^2-x-2} 的麦克劳林展开式为(x)=dfrac (1)({x)^2-x-2}(x)=dfrac (1)({x)^2-