判断函数(x)=ln (sqrt ({x)^2+1}-x)的奇偶性。判断函数的奇偶性。
判断函数(x)=ln (x+sqrt (1+{x)^2})的奇偶性。判断函数的奇偶性。
求极限 lim _(xarrow +infty )dfrac (ln (x+sqrt {{x)^2+1})-ln (x+sqrt ({x)^2-1})}( l
求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^d
44.设 (x)=f(x)(dfrac (1)({2)^x+1}-dfrac (1)(2)), 已知f(x)为奇函数,判断F(x)的奇偶性.
(3)函数f(x)=ln(sqrt(1+x^2)-x)的奇偶性为____;(3)函数$f(x)=ln(\sqrt{1+x^{2}}-x)$的奇偶性为____;
判断函数(x)=ln (sqrt (1+{x)^2}-x)的奇偶性.判断函数的奇偶性.
求下列极限-|||-lim _(xarrow 0)[ dfrac (1)(ln (x+sqrt {1+{x)^2})}-dfrac (1)(ln (1+x))]
.已知 (dfrac (1)(x))=dfrac (4)(x)+2(x)^2+1, 求f(x), ((x)^2+1)
(1) =ln (x+sqrt ({x)^2+1})