直线dfrac (x-1)(1)=dfrac (y-1)(0)=dfrac (z-1)(-1)-|||-__与直线dfrac (x-1)(1)=dfrac (y
求直线dfrac (x-1)(1)=dfrac (y)(1)=dfrac (z-1)(-1)-|||-__ __在平面dfrac (x-1)(1)=dfrac
直线dfrac (x-1)(2)=dfrac (y)(-1)=dfrac (z-2)(3)-|||-__与直线dfrac (x-1)(2)=dfrac (y)(
[题目]-|||-求过点(0,1,2)且与直线 dfrac (x-1)(1)=dfrac (y-1)(-1)=dfrac (z)(2) 垂直相交的直线的方程.
2.设直线 :dfrac (x-1)(1)=dfrac (y)(1)=dfrac (z-1)(-1) 及π -y+2z-1=0.-|||-(1)求直线L在平面π
[题目]直线 dfrac (x+1)(-1)=dfrac (y-2)(1)=dfrac (z-1)(0) 与平面 4x+y+z=1 的-|||-夹角为() ()
直线dfrac (x-1)(1)=dfrac (y)(2)=dfrac (z+3)(-2)-|||-__ __-|||-__与平面dfrac (x-1)(1)=
过直线_(1):dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1)-|||-__ __且平行于直线_(1):dfrac
3、过直线 _(1):dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1) 且平行于直-|||-线 _(2):dfrac
的十面力程.-|||-36求过直线 dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1) 且平行于直线 dfrac (x+