6.单选题-|||-对于任意两事件A与B,与 cup B=B 不等价的是 ()-|||-A .subseteq B-|||-(B) overline (B)subset overline (A)-|||-C .overline (B)=overline (CD)-|||-D) overparen (AB)=overparen (D)

[题目]对于任意二事件A和B,与 cup B=B 不等价-|||-的是 ()-|||-

__-|||-对于任意两个事件A、B,必有 overline (Acap B)=overline (A)cap overline (B)( ) ()A、错B、

(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

设事件A与B互不相容, P(A)=0.4 ,P(B)=0.3 ,则-|||-(overline (A)overline (B))= __ , (overline

设事件A与B互不相容, P(A)=0.4 ,P(B)=0.3 ,则-|||-.(overline (A)overline (B))= __ , (overlin

5.设A,B,C为三个随机事件,且 (overline (A)cup overline (B))=0.8 (overline (A)cup overline (

设事件A与B互不相容, (A)=0.4, P(B)=0.3 ,则-|||-(overline (A)B)= __ , (overline (A)cup B)=

设A，B，C为三个事件，且(overline (A)cup overline (B))=0.9-|||-__ __，(overline (A)cup overl

设A，B，C为三个事件，且P(overline(A)cup overline(B))=0.9，P(overline(A)cup overline(B)cup o

随机事件 A,B 满足 (A)=P(B)=dfrac (1)(2), 且 (Acup B)=1, 则 (overline (A)cup overline (B)