(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B)-B=overline(AB)=A-AB=A-B.

(1)$(\overline{AB}\cup C)(\overline{AC})$; (2)$(A\cup B)(A\cup\overline{B})$. 6.证明:$(A\cup B)-B=\overline{AB}=A-AB=A-B$.

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