5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).

(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

2.设A,B是两个事件,已知 P(A)=1/4 (B)=1/2, (AB)=1/8, 求 (Acup B),-|||-P(AB),P(AB ), [ (Acup

(2)已知P(A)=1/2,P(B)=1/3,P(C)=1/5,P(AB)=1/10,P(AC)=1/15,P(BC)=1/20,P(ABC)=1/30,求Ac

3.指出下列等式和命题是否成立,并说明理由:-|||-(1) cup B=(AB)cup B;-|||-(2) overline (A)B=Acup B:-||

已知(overline (Acup B))=0.2 P(B)=0.5，问（1），P(A-B)= ;(2)(overline (Acup B))=0.2

A Acup B=Omega B AB=emptyset C P(overline(A)cupoverline(B))=1 D P(A-B)=

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

(1)设事件A与B相容,则有 ()-|||-(A) (Acup B)=P(A)+P(B);-|||-(B) (Acup B)=P(A)+P(B)-P(AB);-