二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).

3.指出下列等式和命题是否成立,并说明理由:-|||-(1) cup B=(AB)cup B;-|||-(2) overline (A)B=Acup B:-||

随机事件 A,B 满足 (A)=P(B)=dfrac (1)(2), 且 (Acup B)=1, 则 (overline (A)cup overline (B)

(5)设 (A)=dfrac (1)(3), (B)=dfrac (1)(4), (Acup B)=dfrac (1)(2), 则 (overline (A)c

1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b

已知(overline (Acup B))=0.2 P(B)=0.5，问（1），P(A-B)= ;(2)(overline (Acup B))=0.2

10.证明下列事件的运算公式:()-|||-(1) =ABcup Aoverline (B); __-|||-(2) cup B=Acup overline (

10.证明下列事件的运算公式:-|||-(1) =ABcup Aoverline (B);-|||-__-|||-(2) cup B=Acup overline

已知 (overline (A))=0.3 (B)=0.4, (Aoverline (B))=0.5, 求 (B|Acup overline (B))...