10.证明下列事件的运算公式:()-|||-(1) =ABcup Aoverline (B); __-|||-(2) cup B=Acup overline (A)B.

10.证明下列事件的运算公式:-|||-(1) =ABcup Aoverline (B);-|||-__-|||-(2) cup B=Acup overline

证明下列事件的运算公式：(1) =ABcup Aoverline (B) __(1) =ABcup Aoverline (B) __证明下列事件的运算公式：

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

随机事件 A,B 满足 (A)=P(B)=dfrac (1)(2), 且 (Acup B)=1, 则 (overline (A)cup overline (B)

3.指出下列等式和命题是否成立,并说明理由:-|||-(1) cup B=(AB)cup B;-|||-(2) overline (A)B=Acup B:-||

1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b

(5)设 (A)=dfrac (1)(3), (B)=dfrac (1)(4), (Acup B)=dfrac (1)(2), 则 (overline (A)c