[例1.20]设f`(x)连续, (0)=0, '(0)neq 0, 求 lim _(xarrow 0)dfrac ({int )_(0)^(x^2)f((x)^2-t)dt}({x)^3(int )_(0)^1f(xt)dt}

设f`(x)连续, (0)=0, (0)=2, 极限 lim _(xarrow 0)dfrac ({int )_(0)^xln cos (x-t)dt}(sqr

[例15]设f(x)连续可导,且 lim _(xarrow 0)([ 1+x+dfrac {f(x))(x)] }^dfrac (1{x)}=(e)^3, 求f

设 F(x) = int_(0)^x tf(x^2-t^2) , dt, f(x) 在 x=0 某邻域内可导，且 f(0)=0, f(0)=1，则 lim_(x

设f(x)连续, varphi (x)=(int )_(0)^1f(xt)dt, 且 lim _(xarrow 0)dfrac (f(x))(x)=A设f(x)

[题目]-|||-设 ((x)_(0))=3 则 lim _(xarrow 0)dfrac (f({x)_(0)+x)-f((x)_(0)-3x)}(x)= _

[例18]设f(x )连续,试求下列函数的导数.-|||-(1)f(t)dt;-|||-(2) (int )_(0)^x(x-t)f(t)dt ;-|||-(3

设函数 f(x) 连续，则 (d)/(dx) int_(0)^x t f(x^2-t^2)dt = ( )A. $xf\left(x^{2}\right)$.B

设y=f(x) 在x0处可导,且 ((x)_(0))=2, 则lim _(xarrow 0)dfrac (f({x)_(0)+2)x-f((x)_(0)-f(x

求下列极限: lim _(xarrow 0)[ dfrac ({int )_(0)^xsqrt (1+{t)^2}dt}(x)+dfrac ({int )_(0

设 函数 f ( x ) 在 x = 0 处可导，且lim _(xarrow 0)dfrac (f(2x)-f(0))(ln (1+3x))=1，则f(0)=(