设 f(x,y)= sin dfrac (1)({x)^2+(y)^2} , ^2+(y)^2neq 0,-|||-0, ^2+(y)^2=0,-|||-考察函数f在原点(0,0)的偏导数.

证明:函数-|||-f(x,y)= ((x)^2+(y)^2)sin dfrac (1)(sqrt {{x)^2+(y)^2}}, ^2+(y)^2neq 0,

函数f(x,y)= dfrac (xy)({x)^2+(y)^2},(x)^2+(y)^2neq 0-|||-0, ^2+(y)^2=0在点（0，0）处（）。

设f(x,y)= ^4+{y)^2},(x)^2+(y)^2neq 0 0,(x)^2+(y)^2=0 .处是否连续？设,试问在点处是否连续？

讨论下列函数的连续性:-|||-^2+(y)^2neq 0,-|||-f(x,y)= ) (y)^2ln ((x)^2+(y)^2) 0,=0;

有关函数f(x,y)= dfrac (xy)(sqrt {{x)^2+(y)^2}},(x)^2+(y)^2neq 0-|||-)在点（0，0）的性态，下列说法

二元函数f(x,y)= ^2+{y)^2},(x,y)neq (0,0 0,(x,y)=(0,0) .在点(0,0)处( ).(A)连续,偏导数存在 (B

2【单选题】设f(x,y)=}(x^2+y^2)sin(1)/(sqrt(x^2)+y^(2)),(x,y)neq(0,0)0,(x,y)=(0,0)f(x,y

设函数y=f(x)由方程(y)^2+(y)^2ln x-4=0所确定,则(y)^2+(y)^2ln x-4=0= ( )(y)^2+(y)^2ln x-4=0(

设 (x,y)=dfrac ({x)^2+(y)^2}({e)^xy+xysqrt ({x)^2+(y)^2}} ,则 (f)_(x)(1,0)= __ _.

10.判断题-|||-二元函数-|||-.f(x,y)= ^2+{y)^2}}(x,y)neq (0,0) 0,(x,y)=(0,0) .-|||-点(0