用牛顿法求方程^3-3x-1=0在^3-3x-1=0之间的近似根,计算保留6位有效数字。要求^3-3x-1=0,取1和2作为初始值。

对于方程^3-3x-1=0(1) 分析方程的正根范围.(2) 可以构造迭代公式:^3-3x-1=0,^3-3x-1=0 分析两种迭代法的收敛性(2) 用Ne

求齐次线性方程组 ) (x)_(1)+2(x)_(2)+(x)_(3)-(x)_(4)=0 3(x)_(1)+6(x)_(2)-(x)_(3)-3(x)_(4

用列主元消去法解方程组 ) 3(x)_(1)-(x)_(2)+4(x)_(3)=1 -(x)_(1)+2(x)_(2)-9(x)_(3)=0 -4(x)_(1

解方程组： ) (x)_(1)-(x)_(2)-(x)_(3)=2 2(x)_(1)-(x)_(2)-3(x)_(3)=1 3(x)_(1)+2(x)_(2)

设线性方程组为 ) (x)_(1)-3(x)_(2)-(x)_(3)=0 (x)_(1)-4(x)_(2)+a(x)_(3)=b 2(x)_(1)-(x)_(

方程组 ) (x)_(1)+(x)_(2)+2(x)_(3)=0 3(x)_(1)+4(x)_(2)=1 (x)_(2)-6(x)_(3)=1 .是自由变量

用克莱姆法则求解方程组 ) 2(x)_(1)-3(x)_(2)-3=0 3(x)_(1)-(x)_(2)-8=0 .用克莱姆法则求解方程组，其中是。

已知线性方程组 ) a(x)_(1)+(x)_(3)=1 (x)_(1)+a(x)_(2)+(x)_(3)=0 (x)_(1)+2(x)_(2)+a(x)_(

用消元法解线性方程组 ) (x)_(1)+2(x)_(3)-4(x)_(3)=1 (x)_(2)+(x)_(3)=0 -(x)_(3)=2 .用消元法解线性

16.线性方程组 ) (x)_(1)+(x)_(3)=0 2(x)_(2)+(x)_(3)=0 2(x)_(1)+3(x)_(2)=0 .16.线性方程组用