若W的晶格常数为a,其(111)和(110)面的晶面间距分别为()。-|||-A .dfrac (sqrt {3)}(3)a,dfrac (sqrt {2)}(2)a-|||-(B) dfrac (sqrt {3)}(6)a,dfrac (sqrt {2)}(4)a-|||-(C) dfrac (sqrt {3)}(3)a,dfrac (sqrt {2)}(4)a-|||-(D) dfrac (sqrt {3)}(6)a,dfrac (sqrt {2)}(2)a

11.单选题-|||-已知晶格常数为a,则体心立方晶格中,原子-|||-半径为:-|||-A .dfrac (sqrt {3)}(3)a-|||-(B) dfr

[题目]-|||-求曲线 ^dfrac (2{3)}+(y)^dfrac (2{3)}=(a)^dfrac (2{3)} 在点 (dfrac (sqrt {2)

dfrac (1)(2)-|||-C .dfrac (sqrt {2)}(2)-|||-D .dfrac (sqrt {3)}(2)

2.求曲线 ^dfrac (2{3)}+(y)^dfrac (2{3)}=(a)^dfrac (2{3)} 在点 (dfrac (sqrt {2)}(4)a,d

2.求曲线 ^dfrac (2{3)}+(y)^dfrac (2{3)}=(a)^dfrac (2{3)} 在点 (dfrac (sqrt {2)}(4)a,d

sqrt (dfrac {3g)(l)}-|||-C. sqrt (dfrac {3g)(2)}-|||-D. sqrt (dfrac {8)(3)}

dfrac (sqrt {3)}(2)sin (15)^circ +dfrac (1)(2)cos (15)^circ 的值为( )A．dfrac

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

(8)函数 =dfrac ({x)^2}(sqrt {1-{x)^2}} 在区间 [ dfrac (1)(2),dfrac (sqrt {3)}(2)] 上的

复数=dfrac ((sqrt {3)+i)(2-2i)}((sqrt {3)-i)(2+2i)}的三角形式为( )=dfrac ((sqrt {3)+i)(2