. . .-|||-.-dfrac (2)(3)pi +2kpi ,k=0.pm 1 . . . .-|||-(C) dfrac (1)(3)pi +2kpi
) ( )-|||-(A) =pm (2k+1) (B) =pm 2k-|||-(C) =pm dfrac (1)(2)(2k+1) (D) =pm dfrac
=dfrac ({n)^2h}(8m/{s)^2}-|||-B omega =(x)=sqrt (dfrac {2)(t)}sin (dfrac ({n)^2p
+dfrac (sin n)({2)^n} ;-|||-(2) _(n)=1+dfrac (1)({2)^2}+dfrac (1)({3)^2}+... +df
lim _(narrow infty )(dfrac (1)({n)^2+(e)^-1+1}+dfrac (2)({n)^2+(e)^-2+2}+dfrac (
11.已知 f(0)=0 f(0)=2 ,则 lim _(narrow infty )([ f(dfrac {1)({n)^2})-dfrac (1)({n)^
+(n)^3);-|||-(2) lim _(narrow infty )n[ dfrac (1)({(n+1))^2}+dfrac (1)({(n+2))^2
10【填空题】计算N=A+B,其中:A=(71.3pm0.5)cm^2,B=(6.262pm0.002)cm^2,把结果写成标准形式正确的是N=77.6pm_c
+dfrac (1)(n(n+1)) =-|||-(3) lim _(narrow infty )(dfrac (1)(2)+dfrac (3)({2)^2}+
根据公式 =dfrac (8FLD)(pi {d)^2bDelta n} ,式中 Delta n 为每加1.000kg力标尺读数的变化。计算-|||-金属丝的杨