(-3+4i)=ln 5+i(2kpi +pi -arctan dfrac (4)(3))-|||-A.对-|||-B.错 二
) ( )-|||-(A) =pm (2k+1) (B) =pm 2k-|||-(C) =pm dfrac (1)(2)(2k+1) (D) =pm dfrac
dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi
3.要使函数φ(x )= ,dfrac {pi )(2)] (B)[π,2π] (C) [ 0,dfrac (pi )(2)] (D) [ dfrac
dfrac (1)(2)pi .-|||-C.π-|||-D. dfrac (5)(4)pi .-|||-0
(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}
【题目】 (int )_(0)^dfrac (pi {2)}cos xdx= ()-|||-A、 dfrac (1)(2)-|||-B、1-|||-C、 -df
(3) (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx= () .-|||-(A) dfrac (pi )(8)+
(B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).
[1.21]已知封闭的圆环中粒子的能级为-|||-E =dfrac ({n)^2(h)^2}(8{pi )^2m(R)^2} .n=0 ,pm 1 ,pm 2