积分
=______
积分
=______
计算(int )_(c)_(c)dfrac (cos z)((z-dfrac {1)(2))(z-1)}dz,其中(int )_(c)_(c)dfrac (co
曲线C为正向圆周|z|=2, (int )_(c)dfrac (cos z)({(z-1))^3}dz=曲线C为正向圆周A.0B.C.D.
曲线C为正向圆周|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=
5.利用留数计算下列积分.-|||-(3) (int )_(|z|=2)dfrac ({e)^2z}((z+1){(z-1))^2}dz
5.证明 (z)=cos (z+dfrac (1)(z)) 用z的幂表出的洛朗展开式中的系数为-|||-_(n)=dfrac (1)(2pi )(int )_(
4.不用计算,验证下列积分之值为零,其中C均为单位圆周 |z|=1.-|||-(1) (int )_(c)^dzdfrac (dz)(cos z);-|||-(
15.不定积分 int cos (3x-dfrac (pi )(4))dx=
3.6 计算 (int )_(c)dfrac (1)({z)^2-z}dz, 其中C为圆周 |z|=2.
设C为正向圆周|z|=2, 则下列积分值不为0的是( )A.int dfrac (z)(z-1)dxB.int dfrac (z)(z-1)dxC.
例8 已知 (z)=dfrac (1)(2pi )(|)_(|i|=1)dfrac (cos xi )({(xi -z))^3}ds, 证明:当 |z|neq