恒成立,求实数a的取值范围.-|||-57.已知函数 (x)=2(k)^2x+k(kneq 0) ,x∈[0,1], (x)=3(x)^2-2((k)^2+k+1)x+5(kneq 0),-|||-in [ -1,0] , 存在 _(1)in [ 0,1] , _(2)in [ -1,0] , 使得 ((x)_(2))=f((x)_(1)) 成立,求k的取值范伟-|||-58.已知函数 (x)=2k(x)^2+kx-1-|||-(1)若不等式 (x)lt 0 的解集为 (-dfrac (3)(2),1), 求实数 k的值;-|||-(2)若方程 f(x)=0 在l3 ,2]21有解,求实数k的取.值范围.-|||-59.设 (x)=(x)^2-(a-1)x+a-2-|||-(1)若不等式 (x)geqslant -2 对一切实数x恒成立,求实数a的取值.范围;-|||-(2)解关于x的不等式 (x)lt 0,(ain R).-|||-60.设 (x)=2(x)^2+mx-(m-dfrac (9)(8))(min R)-|||-(1)解不等式 (x)lt 0;-|||-(2)已知存在 _(1),(x)_(2)in R, _(1)lt (x)_(2), 满足 ((x)_(1))=f((x)_(2))=0, 证明:当 _(2)-(x)_(1)cdot 1 时,∫(x)的图象`j x 轴-|||-围成封闭区域的面积大于 dfrac (1)(4).-|||-61.已知二次函数f `(x)满足 f(-1)=8 且 f(0)=f(4)=3-|||-(1)求f(x)的解析式;-|||-(2)若 in [ t,t+1] , 试求 y=f(x) 的最小值.

参考答案与解析:

相关试题

若_(1)+((k)^2+1)(x)_(2)+2(x)_(3)=0-|||-_(1)+(2k+1)(x)_(2)+2(x)_(3)=0-|||-(x)_(1)+k(x)_(2)+(2k+1)(x)_(

若_(1)+((k)^2+1)(x)_(2)+2(x)_(3)=0-|||-_(1)+(2k+1)(x)_(2)+2(x)_(3)=0-|||-(x)_(1)+

  • 查看答案
  • X=k =dfrac (c)(k!) ,=0, 1,2,3...... X=k =dfrac (c)(k!) ,=0, 1,2,3...... X=k =dfrac (c)(k!) ,=0, 1,2,

    X=k =dfrac (c)(k!) ,=0, 1,2,3...... X=k =dfrac (c)(k!) ,=0, 1,2,3...... X=k =dfr

  • 查看答案
  • 已知关于x的方程 ^2+(2k-3)x+(k)^2-3=0 有两个实数根x1,x2,且 _(1)+(x)_(2)=dfrac (1)({x)_(1)}+dfrac (1)({x)_(2)}, 求k的值

    已知关于x的方程 ^2+(2k-3)x+(k)^2-3=0 有两个实数根x1,x2,且 _(1)+(x)_(2)=dfrac (1)({x)_(1)}+dfra

  • 查看答案
  • 设线性方程组(X)_(1)+(X)_(2)-(X)_(3)=-12(X)_(1)+K(X)_(2)-2(X)_(3)=0K(X)_(1)+2(X)_(2)+(X)_(3)=K(1)K为何值时,方程组有

    设线性方程组(X)_(1)+(X)_(2)-(X)_(3)=-12(X)_(1)+K(X)_(2)-2(X)_(3)=0K(X)_(1)+2(X)_(2)+(X

  • 查看答案
  • M~m-M-|||-k1 k2-|||-(B) =(x)_(0)cos [ sqrt (dfrac {{k)_(1)(k)_(2)}(m({k)_(1)+(k)_(2))}}] 0 x0 x-|||

    M~m-M-|||-k1 k2-|||-(B) =(x)_(0)cos [ sqrt (dfrac {{k)_(1)(k)_(2)}(m({k)_(1)+(k)

  • 查看答案
  • 一个反比例函数=dfrac (k)(x)(kneq 0)经过点 ( 2 , 6 ) ,则 k = _ .

    一个反比例函数=dfrac (k)(x)(kneq 0)经过点 ( 2 , 6 ) ,则 k = _ .一个反比例函数经过点(2,6),则k=_.

  • 查看答案
  • 已知x_(1)[k]=-1,1,0,2,1,0,-1,x_(2)[k]=1,2,3,-1,-1,-1,-1,画出下列离散序列的波形。(1) y_(1)[k]=x_(1)[k]+x_(2)[k];(2)

    已知x_(1)[k]=-1,1,0,2,1,0,-1,x_(2)[k]=1,2,3,-1,-1,-1,-1,画出下列离散序列的波形。(1) y_(1)[k]=x

  • 查看答案
  • [题目]设线性方程组 _(1)+(X)_(2)-(X)_(3)=-1-|||-(X)_(1)+K(X)_(2)-2(X)_(3)=0-|||-(X)_(1)+2(X)_(2)+(X)_(3)=K-||

    [题目]设线性方程组 _(1)+(X)_(2)-(X)_(3)=-1-|||-(X)_(1)+K(X)_(2)-2(X)_(3)=0-|||-(X)_(1)+2

  • 查看答案
  • )-|||-B .(X=k)=dfrac (1)({3)^k}(k=1,2,... )-|||-C .(X=k)=dfrac (1)({3)^k}(k=0,1.2... )-|||-! D .(X=

    )-|||-B .(X=k)=dfrac (1)({3)^k}(k=1,2,... )-|||-C .(X=k)=dfrac (1)({3)^k}(k=0,1

  • 查看答案
  • 已知函数 f(x) = ln(1+x) - x + (1)/(2) x^2 - kx^3,其中 0 < k < (1)/(3)。(1) 证明:f(x) 在区间 (0, +i

    已知函数 f(x) = ln(1+x) - x + (1)/(2) x^2 - kx^3,其中 0 < k < (1)/(3)。(1) 证明:f(x) 在区间

  • 查看答案