(2)(e^x+y-e^x)dx+(e^x+y+e^y)dy=0;

(6) (e^x+y-e^x)dx+(e^x+y+e^y)dy=0;(6) $(e^{x+y}-e^{x})dx+(e^{x+y}+e^{y})dy=0;$

求微分方程(e^x+y-e^x)dx+(e^x+y+e^y)dy=0的通解。(用分离变量法)求微分方程$$(e^{x+y}-e^x)dx+(e^{x+y}+e^

(5) ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0 ;

(7) ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0;-|||-d

2.求微分方程 ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0 的通解.-|||-

1.求下列微分方程的通解:-|||-(6) ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0; ()

微分方程 (e^x+y - e^x)dx + (e^x+y + e^y)dy = 0 的通解为A. $(e^x + 1)(e^y + 1)= C$B. $(e^

(6)(1+2e^x/y)dx+2e^x/y(1-(x)/(y))dy=0.(6)$(1+2e^{x/y})dx+2e^{x/y}(1-\frac{x}{y})

6.求下列全微分的原函数:-|||-(1) ((x)^2+2xy-(y)^2)dx+((x)^2-2xy-(y)^2)dy-|||-(2) ^x[ e(x-y+

设曲线积分I=|y[φ(x)- e^x]dx-φ(x)dy与路径无关，其中I=|y[φ(x)- e^x]dx-φ(x)dy可导且I=|y[φ(x)- e^x]d