设曲线积分I=|y[φ(x)- e^x]dx-φ(x)dy与路径无关，其中I=|y[φ(x)- e^x]dx-φ(x)dy可导且I=|y[φ(x)- e^x]dx-φ(x)dy，求I=|y[φ(x)- e^x]dx-φ(x)dy.

五、设曲线积分(int )_(L)x(y)^2dx+yf(x)dy与路径无关,其中(int )_(L)x(y)^2dx+yf(x)dy具有连续导数,且(int

(5) ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0 ;

(6) (e^x+y-e^x)dx+(e^x+y+e^y)dy=0;(6) $(e^{x+y}-e^{x})dx+(e^{x+y}+e^{y})dy=0;$

(2)(e^x+y-e^x)dx+(e^x+y+e^y)dy=0;(2)$(e^{x+y}-e^{x})dx+(e^{x+y}+e^{y})dy=0;$

(7) ((e)^x+y-(e)^x)dx+((e)^x+y+(e)^y)dy=0;-|||-d

设函数y=y(x)由方程e x-e y=sin(xy)所确定,求dy/dx|x=0设函数y=y(x)由方程e x-e y=sin(xy)所确定,

已知曲线积分(int )_(t)^yf(x)dx+((x)^2+y)dy与路径无关，则(int )_(t)^yf(x)dx+((x)^2+y)dy_____.已

(3)设D=((x,y)|x²+y²≤4),计算I=iintlimits_(D)|2x-x^2-y^2|dx dy.(3)设D={(x,y)|x²+y²≤4},

下式中正确的是A.(X+Y)=DX+DY+2Cou(X,Y)B.(X+Y)=DX+DY+2Cou(X,Y)C.(X+Y)=DX+DY+2Cou(X,Y)D.(X

微分方程((a)^x+y-(a)^x)dx+((a)^x+y+(a)^y)dy=0的通解为( )((a)^x+y-(a)^x)dx+((a)^x+y+(a)^y