lim _(x arrow 0)(x+2 e^x)^(1)/(x-1) = ( ).

arrow (overrightarrow (x)-(e)^x-1)-|||-(25) lim _(xarrow 0)((1+{x)^2)}^dfrac (1{

lim_(x arrow 1) (sin^2(x-1))/(x^2)-1$\lim_{x \rightarrow 1} \frac{\sin^{2}(x-1)}

A.lim _(xarrow 1)dfrac ({x)^2+x-2}({x)^2-1}=lim _(xarrow 1)dfrac ((x-1)(x+2))((x

lim _(x arrow 1)((1)/(x-1)-(3)/(x^2-1))= $\lim _{x \rightarrow 1}\left(\frac{1}{

设函数 (x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6}求(x)=(e)^dfrac (1{x-1)}dfra

underset(lim)(x→0)（(1)/(x)-(1)/((e)^x-1)）$\underset{lim}{x→0}$（$\frac{1}{x}$-$\f

极限 lim_(x arrow 0) ( (2 + e^frac(1)/(x))(1 + e^(2)/(x)) + (sin x)/(|ln(1+x)|) )

lim _(x arrow 2) e^(1)/(2-x) = ( )A. $+\infty$B. 0C. -1D. -2

lim_(x to 0) (2^x-1)/(x)= ( )A. ln2B. 2C. 1D. 0

求极限lim _(xarrow 0)dfrac (x({e)^x+1)-2((e)^x-1)}({x)^3}-|||-__求极限