19.若 '((x)_(0))=-2 ,则 lim _(Delta xarrow 0)dfrac (f({x)_(0)+Delta x)-f((x)_(0))}(3Delta x)= ()-|||-

1.已知f`(x0)存在,则由导数定义知, lim _(Delta xarrow 0)dfrac (f({x)_(0)-Delta x)-f((x)_(0))}

(4)设 (x)=(e)^sqrt (x) 则 lim _(Delta xarrow 0)dfrac (f(1+Delta x)-f(1))(Delta x)=

设y=f(x) 在x0处可导,且 ((x)_(0))=2, 则lim _(xarrow 0)dfrac (f({x)_(0)+2)x-f((x)_(0)-f(x

(B)若 lim _(xarrow 0)dfrac (f(x)+f(-x))(x) 存在,则 (0)=0.-|||-(C)若 lim _(xarrow 0)df

[题目]-|||-设 ((x)_(0))=3 则 lim _(xarrow 0)dfrac (f({x)_(0)+x)-f((x)_(0)-3x)}(x)= _

若(0)=0, lim _(xarrow 0)dfrac (f(2x))(x)=4, 则 (0)=若

已知 lim _(xarrow 0)([ 1+x+dfrac {f(x))(x)] }^dfrac (1{x)}=(e)^3, 则 lim _(xarrow 0

9.(2023山东一)已知f(x)在x=3处可导且lim_(Delta xto0)(f(3-2x)-f(3))/(Delta x)=4,则f(3)=（）A. 2

设 lim _(xarrow 0)((1+x+dfrac {f(x))(x))}^dfrac (1{x)}=(e)^3 ,则 lim _(xarrow 0)((

设lim _(xarrow 0)dfrac (ln (1+x+dfrac {f(x))(x))}(x)=3，则lim _(xarrow 0)dfrac (ln