级数 sum _(n=1)^infty (sqrt (n+2)-2sqrt (n+1)+sqrt (n))= __ .

2.lim_(n to infty)(sqrt(n+1)-sqrt(n))sqrt(n+1)=_____.2.$\lim_{n \to \infty}(\sqr

18.-|||-在下列无穷级数中,收敛的级数是 ()-|||-A sum _(n=1)^infty (sqrt (n+1)-sqrt (n));-|||-B s

3.已知 =sqrt (n+1)-sqrt (n) , =sqrt (n+2)-sqrt (n+1) , gt 0 ,试比较a,b的大小.

求级数 sum _(n=1)^infty dfrac (1)(n(n+1)(n+2)) 的和.-|||-__

求级数sum _(n=1)^infty dfrac (1)(n(n+1)(n+2))的和。求级数的和。

=sqrt (n+2)-sqrt (n+1) , gt 0 ,试比较-|||-a,b的大小.

求极限lim_(ntoinfty)(sqrt[n]((n+1)(n+2)...(n+n)))/(n).求极限$\lim_{n\to\infty}\frac{\s

[题目]求值 lim _(narrow infty )(sqrt (n+1)-sqrt (n))

级数sum_(n=1)^infty(3)/(sqrt[3](n^2)+1)收敛A 对B 错二、判断题（共20题，40.0分）50.（判断题，2.0分）级数$\s

[题目]计算 lim _(narrow infty )cos (sqrt (n+1)-sqrt (n))