(a)_(m)+(b)_(1)+(b)_(2)+... +(b)_(n)}(m+n)=-|||-dfrac (m)(m+n)cdot dfrac ({a)_(1
24.已知 ((m)^2+9)((n)^2+1)=5-10mn ,求:-|||-(1) (n+dfrac (1)(n));-|||-(2) ((m-dfrac
=dfrac (T)(2pi )leqslant [ t] =dfrac ([ O] )(2);-|||-_(2)(A)_(1)+dfrac ({M)_(y)}
3 一质量M,半径为R的圆柱-|||-omega =dfrac (2{v)_(0)}(R)-|||-omega =dfrac (m{v)_(0)}((M+m)R
(g)^2(m)^2-|||-_(n)=259.0times (10)^-6N-8(m)^2PH=2.155-|||-_(c)=dfrac ({U)_(a)d}
18.reverse logistics() ()-|||-A反向物流-|||-B生产物流-|||-dfrac (FE)(FE)=dfrac (1)(n)-||
+dfrac (1)(n))}^dfrac (1{n)};
+dfrac (sin n)({2)^n} ;-|||-(2) _(n)=1+dfrac (1)({2)^2}+dfrac (1)({3)^2}+... +df
,dfrac (ntimes 100)(n)} B S=-|||- dfrac {1)(n),... ,dfrac (ntimes 100)(n)} C S=-
25.设总体为韦布尔分布,其密度函数为-|||-(x,m,n)=dfrac (m{x)^m-1}({n)^m}ep[ -((dfrac {x)(n))}^m]