
化简:overrightarrow((overline{AB) cup C) (overline(AC))} 化简:$\overrightarrow{(\ove
一.化简overline (AB)cup C)(overline (AC))一.化简
(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B
overline (C)+AB-|||-D . C+AB
2.3.1 用代数法将下列各式化简成最简的与-或表达式:-|||-(1) overline (AB+overline {A)}overline (B)+over
2.1.4 某逻辑函数的对偶式 =overline (A)Bcdot (overline (BC)+overline (D)) ,则该逻辑函数 L= __ ,其
三、判断以下等式是否成立1) A∪B=AB∪B; ( )2) overline(A∪BC)=overline(B∪C); ( )3) 若overline
函数=overline (A)(B+overline (C)cdot overline (DE)) 的反函数是-|||-__ __( )A、=overline
5.设随机事件A,B,C的概率都是 1/2, 且 (ABC)=P(overline (A)cap overline (B)cap overline (C)) ,
2.3.1 用代数法将下列各式化简成最简的与-或表达式:-|||-(1) overline (AB+overline {A)B}+overline (A)B+A