化简:$\overrightarrow{(\overline{AB} \cup C) (\overline{AC})}$
一.化简overline (AB)cup C)(overline (AC))一.化简
(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B
=AB+overline (AC)+overline (BC)+overline (C)D+overline (D) __-|||-__ __
5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).
5.设A,B,C为三个随机事件,且 (overline (A)cup overline (B))=0.8 (overline (A)cup overline (
二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))
1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b
设A,B,C为三个事件,且P(overline(A)cup overline(B))=0.9,P(overline(A)cup overline(B)cup o
设A,B,C为三个事件,且(overline (A)cup overline (B))=0.9-|||-__ __,(overline (A)cup overl
用代数法将下列各式化简成最简的与-或表达式.(1) (A+B)+(A+B)+(AB)(overline(AB))(2) B+overline(ABC)+AC+A